Question

Calculate the energy of a single photon of blue light with a wavelength of 4.63×102 nm.

Answer 1

Answer on Question#49070 – Physics – Optics

Calculate the energy of a single photon of blue light with a wavelength of $4.63 \times 10^{2} \, \text{nm}$

**Solution:**

$$\begin{array}{l} \lambda = 4.63 \times 10^{2} \, \text{nm} \, (4.63 \times 10^{-7} \, \text{m}) \, \text{(wavelength)}; \\ c = 3 \times 10^{8} \, (\text{m/s}); \, \text{(speed of light)}; \\ h = 6.63 \times 10^{-34} \, (\text{J*s}) \, \text{(Planck constant)}; \\ E = h v; \, v = \frac{c}{\lambda}; \, E = \frac{hc}{\lambda}; \\ E = 4.3 \times 10^{-19} \, \text{J}; \\ \text{Answer: } 4.3 \times 10^{-19} \, \text{J}; \end{array}$$

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