Question

a beam of light strikes the side of a glass of water with an angle of incidence of 25 degrees, find the angle of refraction?

Answer 1

Answer on Question #44577-Physics-Optics

A beam of light strikes the side of a glass of water with an angle of incidence of 25 degrees, find the angle of refraction?

Solution

We can use formula

$$n = \frac {\sin \theta_ {\mathrm {incidence}}}{\sin \theta_ {\mathrm {refraction}}},$$

where $n = 1.333$ is the index of refraction of water, $\theta_{\mathrm{incidence}}$ is an angle of incidence, $\theta_{\mathrm{refraction}}$ is the angle of refraction.

So

$$\theta_ {\mathrm {refraction}} = \sin^ {- 1} \left(\frac {\sin \theta_ {\mathrm {incidence}}}{n}\right) = \sin^ {- 1} \left(\frac {\sin 25{}^{\circ}}{1.333}\right) = 18.5{}^{\circ}.$$

Answer: $18.5{}^{\circ}$

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