Question #39086

Starting from Maxwell’s field equations in free space, derive wave equation

Expert's answer

Answer on Question 39086, Physics, Optics Maxwells field equations in free space are

E=0\nabla\cdot\mathbf{E}=0

×E=Bt\nabla\times\mathbf{E}=\frac{\partial\mathbf{B}}{\partial t}

B=0\nabla\cdot\mathbf{B}=0

×B=1c2Et\nabla\times\mathbf{B}=\frac{1}{c^{2}}\frac{\partial\mathbf{E}}{\partial t}

To derive wave equation we will take curl of the curl equations and use curl of the curl identity:

×(×E)=(E)2E\nabla\times(\nabla\times\mathbf{E})=\nabla\cdot(\nabla\cdot\mathbf{E})-\nabla^{2}\mathbf{E}

We know that E\nabla\cdot\mathbf{E}. From the other hand, from equations we see that

×(×E)=×(Bt)=(×B)t=1c22Et2\nabla\times(\nabla\times\mathbf{E})=-\nabla\times(\frac{\partial\mathbf{B}}{\partial t})=-\frac{\partial(\nabla\times\mathbf{B})}{\partial t}=-\frac{1}{c^{2}}\frac{\partial^{2}E}{\partial t^{2}}

All together give us

1c22Et22E=0\frac{1}{c^{2}}\frac{\partial^{2}\mathbf{E}}{\partial t^{2}}-\nabla^{2}\mathbf{E}=0

In the very same way we get

1c22Bt22B=0\frac{1}{c^{2}}\frac{\partial^{2}\mathbf{B}}{\partial t^{2}}-\nabla^{2}\mathbf{B}=0

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