Question #37066

Walter Light Wave and Percy Photon decide to have a race. Walter runs the entire race in air while Percy slogs his way through crown glass. If Walter beats Percy by 1.34E-6 s, how long was the race?

Expert's answer

Question 37066

Walter Light Wave and Percy Photon decide to have a race. Walter runs the entire race in air while Percy slogs his way through crown glass. If Walter beats Percy by 1.34E-6 s, how long was the race?

A light wave and a photon are essentially the same thing due to the light dualism.

The difference in the travel time is due to the different refraction indices, nW=1n_{W}=1 for air (Walter) and nP=1.52n_{P}=1.52 for the crown glass (Percy). The speed of a photon in a given medium is v=cnv=\frac{c}{n}.

We are given information that tPtW=1.34×106t_{P}-t_{W}=1.34\times 10^{-6} s.

If the length of the race is L, the travel times can be calculated as t=Lv=Lnct=\frac{L}{v}=\frac{Ln}{c}.

This way the equation for time difference transforms into L(nPnW)c=1.34×106\frac{L(n_{P}-n_{W})}{c}=1.34\times 10^{-6} s.

From this we can work out L=(1.34×106s)×c(nPnW)L=\frac{(1.34\times 10^{-6}s)\times c}{(n_{P}-n_{W})}.

Using the numerical values,

L=(1.34×106s)×3×108ms(1.521.00)773.08L=\frac{(1.34\times 10^{-6}s)\times 3\times 10^{8}\frac{m}{s}}{(1.52-1.00)}\approx 773.08 m.

Answer: about 773 m.


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