Question #348009

If the density of water is 1,00 g/cm3 and atmospheric pressure is 1,013 × 105 Pa, the depth in water (in m) where the absolute pressure is four times atmospheric pressure, is equal to


1
Expert's answer
2022-06-06T08:54:32-0400

ρghp+1=4,\frac{\rho gh}p+1=4,

h=3pρg=31 m.h=\frac{3p}{\rho g}=31~m.


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