Answer to Question #348009 in Optics for INGA

Question

If the density of water is 1,00 g/cm³ and atmospheric pressure is 1,013 × 10⁵ Pa, the depth in water (in m) where the absolute pressure is four times atmospheric pressure, is equal to

Answer 1

$\frac{\rho gh}p+1=4,$

$h=\frac{3p}{\rho g}=31~m.$