If the density of water is 1,00 g/cm3 and atmospheric pressure is 1,013 × 105 Pa, the depth in water (in m) where the absolute pressure is four times atmospheric pressure, is equal to
ρghp+1=4,\frac{\rho gh}p+1=4,pρgh+1=4,
h=3pρg=31 m.h=\frac{3p}{\rho g}=31~m.h=ρg3p=31 m.
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