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Question #343408
A concave mirror has a 7.0 cm focal length. A 2.4 cm object is 16.0 cm from the mirror. Determine the image height.
Expert's answer
The mirror equation says
1
d
i
+
1
d
o
=
1
f
\frac{1}{d_i}+\frac{1}{d_o}=\frac{1}{f}
d
i
1
+
d
o
1
=
f
1
1
d
o
=
1
f
−
1
d
i
\frac{1}{d_o}=\frac{1}{f}-\frac{1}{d_i}
d
o
1
=
f
1
−
d
i
1
1
d
o
=
1
7.0
−
1
16
\frac{1}{d_o}=\frac{1}{7.0}-\frac{1}{16}
d
o
1
=
7.0
1
−
16
1
d
o
=
12
c
m
d_o=12\:\rm cm
d
o
=
12
cm
h
i
h
o
=
d
i
d
o
\frac{h_i}{h_o}=\frac{d_i}{d_o}
h
o
h
i
=
d
o
d
i
h
i
=
h
o
d
i
d
o
=
2.4
∗
12
16
=
1.9
c
m
h_i=h_o\frac{d_i}{d_o}=2.4*\frac{12}{16}=1.9\:\rm cm
h
i
=
h
o
d
o
d
i
=
2.4
∗
16
12
=
1.9
cm
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