What mass of silver salt is deposited when a current of 2.6 A is passed though a solution of a silver salt for 40 minutes? (ag=108 F=96500C)
We know that
Time (t)="40\\times60=2400sec"
"I=2.6A"
Charge "(Q)=it"
"Q=2.6\\times40\\times60=6240C"
96500C charge deposit=1 mol of Ag
1C charge deposit ="\\frac{108}{96500}"
6240C charge deposit =
"\\frac{108}{96500}\\times6240=6.98gm"
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