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Answer to Question #310036 in Optics for Big Insect

Question #310036

The number of atoms of chlorine present in 5.85g of Nacl is ?( Na =23 Cl=35.5)(Avogadro's number=6.02*10


1
Expert's answer
2022-03-14T13:07:50-0400

Answer

The number of atoms of chloride present in 5.85g of NaCl is

"5.85 *6.02 * 10\n^{23}\n= 35.22*10^{23}atoms"



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