Question

The number of atoms of chlorine present in 5.85g of Nacl is ?( Na =23 Cl=35.5)(Avogadro's number=6.02*10

Answer 1

Answer

The number of atoms of chloride present in 5.85g of NaCl is

$5.85 *6.02 * 10 ^{23} = 35.22*10^{23}atoms$