Numerical aperture of a fibre is 0.5 and core refractive index is 1.48. Find cladding refractive index and acceptance angle .
β=n22−n12=1.09,\beta=\sqrt{n_2^2-n_1^2}=1.09,β=n22−n12=1.09,
α=arctan0.5=26.6°.\alpha=\arctan 0.5=26.6°.α=arctan0.5=26.6°.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments