Answer to Question #302959 in Optics for amandachan

Question #302959

1 decibel at 500 nm is 100 W, what is the number of watts at 550 nm?

Expert's answer

Answer

Power is inversely proportional to wavelength.

So

New power

"P'=\\frac{P*\\lambda}{\\lambda'}\\\\=\\frac{500nm*100W}{550nm}\\\\=90.91W"

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