assuming that the resolving power of the eye is determined by diffraction effects only, calculate the maximum distance at which two objects separated by a distance of 2 m can be resolved by the eye. (assume pupil diameter to be 2 mm and λ = 6000 å.)
λl=sd2,\lambda l=\frac{sd}2,λl=2sd,
l=sd2λ=3.3 km.l=\frac{sd}{2\lambda}=3.3~km.l=2λsd=3.3 km.
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