A 1.6 m tall girl stands 3.2 m from a convex mirror . What is the focal length of the mirror if her image appears to be 0.28 m tall?
m=hiho=−didom=\frac{h_i}{h_o}=-\frac{d_i}{d_o}m=hohi=−dodi
di=−hidohod_i=-\frac{h_i d_o}{h_o}di=−hohido
=−(0.28m)(3.2m)1.6m=−0.56m=-\frac{(0.28m)(3.2m)}{1.6m} =-0.56m=−1.6m(0.28m)(3.2m)=−0.56m
1f=1do+1di\frac{1}{f}=\frac{1}{d_o}+\frac{1}{d_i}f1=do1+di1
f=dodido+dif=\frac{d_o d_i}{d_o+d_i}f=do+didodi
=(3.2m)(−0.56m)3.2m+(−0.56m)=−0.68m=\frac{(3.2m)(-0.56m)}{3.2m+(-0.56m)}=-0.68m=3.2m+(−0.56m)(3.2m)(−0.56m)=−0.68m
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments