Question #285638

Compare the mirror equation with the thin lens equation. Discuss similarities and differences, especially the sign conventions for the quantities involved.

1
Expert's answer
2022-01-12T08:31:46-0500

the mirror equation is 1v1u=1f\frac{1}{v}- \frac{1}{u}=\frac{1}{f} lens equation is 1v+1u=1f\frac{1}{v}+\frac{1}{u}=\frac{1}{f} where v=v= image distance u=object distancef=f= focal length

Below applies to: Mirror and Thin Lens Equation: 1do+1di=1f\frac{1}{do}+\frac{1}{di}=\frac{1}{f}

 Magnification Equation: Image height/Object height =hiho=dido=\frac{hi}{ho}=-\frac{di}{do}


 Spherical Mirrors Lenses 

Focal Length (f)

+ for concave mirrors 

+ for a converging lens 

- for convex mirrors 

- for a diverging lens 


Object Distance (do) 

+ if object is in front of the mirror (real object)

+ if the object is to the left of the lens (real object) 

- if object is behind the mirror (virtual object)

 - if the object is to the right of the lens (virtual object)


Image Distance (di) 

+ if the image is in front of the mirror (real image)

+ for an image (real) formed to the right of the lens by a real object 

- if the image is behind the mirror (virtual image)

- for an image (virtual) formed to the left of the lens by a real object 


Magnification (m) 

+ for an image that is upright with respect to the object

+ for an image that is upright with respect to the object 

- for an image that is inverted with respect to the object

-for an image that is inverted with respect to the object. 


 Optical system that use multiple mirrors/lenses sometimes use the image formed by the first mirror/lens as the object for the second mirror/lens. When this happens, the object distance is negative and the object is said to be a virtual object. 

 


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS