Question

Given the dimensions of the reduced eye , the

diameter fovea ab = 0.3mm. view distance nB= nA=2.05

meters, na = nb = 1.5cm, calculate the object size for an image

filling the fovea.Pay attention to unit 1m=100cm=1000mm;

Answer 1

1) Determine the magnification:

$$M=-\frac{d_i}{d_o}=-\frac{1.5}{205}=7.32·10^{-3}.$$

2) The size of the object:

$$h_o=h_i/M=0.3/(0.00732)=40.98 \text{ mm}.$$