Question

Fing the band width of fringes in an air wedge formed by 2 glass plate of length 30 cm spaced 0.042 mm at one end, wave length-590 nm

Answer 1

$\Delta b=\lambda/2$

$L=\Delta b/\sin\gamma=(\lambda/2)/(0.000042/0.3)=$

$=0.00000059\cdot3571=0.0021\ (m)$