v of light in Material=0.52cθc=sin−1(nlightnmaterial)nmaterial=cvnmaterial=c0.52cnmaterial=10.52nmaterial=1.92θc=sin−1(11.92)θc=31.39°θc=31°{v\,of\,light\,in\,Material=0.52c}\\ {\theta_c=sin^{-1}(\frac{n_{light}}{n_{material}})}\\ {n_{material}=\frac{c}{v}}\\ {n_{material}=\frac{c}{0.52c}}\\ {n_{material}=\frac{1}{0.52}}\\ {n_{material}=1.92}\\ {\theta_c=sin^{-1}(\frac{1}{1.92})}\\ {\theta_c=31.39\degree}\\ {\theta_c=31\degree}\\voflightinMaterial=0.52cθc=sin−1(nmaterialnlight)nmaterial=vcnmaterial=0.52ccnmaterial=0.521nmaterial=1.92θc=sin−1(1.921)θc=31.39°θc=31°
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