Question #268417

X-ray with energy 12 keV is used to measure Bragg-reflection peaks. The third-order peak is measured for the X-ray beam incident at an angle of 30 degrees with

respect to the horizontal. What is the spacing between the atomic planes? What

is the angle at which the first-order reflection peak is observed?


Expert's answer

2dsin⁡α=nλ2d\sin\alpha=n\lambda


hν=hc/λ=E→λ=hc/E=h\nu=hc/\lambda=E\to \lambda=hc/E=


=6.626⋅10−24⋅3⋅108/(12000⋅1.6⋅10−19)==6.626\cdot10^{-24}\cdot3\cdot10^8/(12000\cdot1.6\cdot10^{-19})=


=1.035⋅10−10 (m).=1.035\cdot10^{-10}\ (m).


a. 2dsin⁡30°=3⋅1.035⋅10−10→d=3.1⋅10−10 (m)2d\sin30°=3\cdot1.035\cdot10^{-10}\to d=3.1\cdot10^{-10}\ (m)


b. 2⋅3.1⋅10−10⋅sin⁡α=1⋅1.035⋅10−10→2\cdot3.1\cdot10^{-10}\cdot\sin\alpha=1\cdot1.035\cdot10^{-10}\to


α=9.6°\alpha=9.6°


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