Answer to Question #263630 in Optics for Rethabile

Question #263630

Question 13 (4 points)


A concave mirror has a radius of curvature of 40.5 cm and is positioned at a distance such that the upright image of a person's face is 1.5 times the size of his face. How far is the mirror from the person's face?

Question 13 options:


A) 

No option is correct


B) 

+4.75 cm


C) 

+ 5.75 cm


D) 

+3.75 cm


E) 

+ 6.75 cm

1
Expert's answer
2021-11-14T17:13:03-0500

r=40.5  cmf=r2=20.25  cmv=muv=1.5u1u+1v=1f1u11.5u=120.251.51=1.5u20.250.5=1.5u20.251.5u=10.125u=6.75  cmr=40.5 \; cm \\ f = \frac{r}{2} = 20.25 \;cm \\ v=-mu \\ v = -1.5u \\ \frac{1}{u} + \frac{1}{v} = \frac{1}{f} \\ \frac{1}{u} - \frac{1}{1.5u} = \frac{1}{20.25} \\ 1.5 -1 = \frac{1.5u}{20.25} \\ 0.5 = \frac{1.5u}{20.25} \\ 1.5u = 10.125 \\ u = 6.75 \;cm

Answer: E) +6.75 cm


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment