if focal length of convex lens is f and it is cut into two equal part what is focal length of each part?
1
Expert's answer
2013-03-07T08:55:01-0500
There can be two ways to cut a convex lens into two equal parts - one, along the principal axis and another, perpendicular to the principal axis. If the lens is cut along the principal axis, then there will be NO change in the focal length of the lens. But, if it is cut perpendicular to the principal axis, then the focal length will be twice the original one.
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Assignment Expert
17.07.14, 17:38
Dear Fatima, The focal distance [i]f[/i] of a lens can be calculated
using a lensmaker's equation: [i]1/f = (n - 1)(1/R_1-1/R_2)[/i], where
[i]n[/i] is a refractive index, [i]R_1[/i] and [i]R_2[/i] are
curvature radii. For a biconvex lens the [i]R_2[/i] is taken negative.
If [i]|R_1| = |R_2| = R[/i], we have [i]f = R/(2*(n-1))[/i]. If one
cuts lens perpendicularly to the principal axis, the obtained lens
will be convex only on the one side and flat on another side: [i]R_1 =
R[/i] and [i]R_2 = infinity[/i]. So, [i]1/f_1= (n-1)/R
=>f_1=R/(n-1)=2f[/i].
fatima
19.06.14, 10:28
explain plz?? infact i want to know is there any relation between
diameter and focal length?
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Comments
Dear Fatima, The focal distance [i]f[/i] of a lens can be calculated using a lensmaker's equation: [i]1/f = (n - 1)(1/R_1-1/R_2)[/i], where [i]n[/i] is a refractive index, [i]R_1[/i] and [i]R_2[/i] are curvature radii. For a biconvex lens the [i]R_2[/i] is taken negative. If [i]|R_1| = |R_2| = R[/i], we have [i]f = R/(2*(n-1))[/i]. If one cuts lens perpendicularly to the principal axis, the obtained lens will be convex only on the one side and flat on another side: [i]R_1 = R[/i] and [i]R_2 = infinity[/i]. So, [i]1/f_1= (n-1)/R =>f_1=R/(n-1)=2f[/i].
explain plz?? infact i want to know is there any relation between diameter and focal length?
Leave a comment