How far apart are an object and an image formed by a 75.0cm focal length converging lens if the image is 2.5x larger than the object and is real.
"m = \\frac{v}{u} = 2.5 \\\\\n\n\\frac{1}{u} + \\frac{1}{v} = \\frac{1}{f}"
Multiplying by v on both sides and replacing "\\frac{v}{u}" by m
"m + 1 = \\frac{v}{f} \\\\\n\n3.5 = \\frac{v}{75} \\\\\n\nv = 262.25 \\; cm \\\\\n\nu = \\frac{v}{m} = \\frac{262.25}{2.5} =105 \\; cm \\\\\n\nu +v = 105 +262.25= 367.25 \\; cm"
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