Answer to Question #251810 in Optics for Bee

Question

1. An electron in a uniform electric field experiences a force of4.0×10^-11.what are the magnitude and direction of E at this point?

Answer 1

$E = \large\frac{F}{q}$ $= \large\frac{4*10^{-11}}{1.6*10^{-19}}$ $= 2.5 * 10^8 \large\frac{N}{C}$ - the magnitude of E and it is direction the same with electron