A parallel film of sodium light of wavelength
5880Å is incident on a thin glass plate of μ=1.5 such that
the angle of refraction in the plate is 60o. Calculate the
smallest thickness of the plate which will make it appear
dark at reflection.
2dcosβ=λn, ⟹ 2d\cos\beta=\frac{\lambda}n,\implies2dcosβ=nλ,⟹
d=λ2ncosβ,d=\frac{\lambda}{2n\cos\beta},d=2ncosβλ,
d=0.392 μm.d=0.392~\mu\text{m}.d=0.392 μm.
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