Question #242803

Light travels through a medium with an index of refraction of 1.04.It comes to the surface of another medium at an angle of 83 degree. If the index of refraction for this medium is 2.1, what angle does the refracted light make with respect to the surface?

Expert's answer

n1=1.04;θ1=83°n_1 = 1.04;\theta_1=83\degree

n2=2.1;n_2 = 2.1;

by Snell’s Law:\text{by Snell's Law:}

n1sinθ1=n2sinθ2n_1\sin\theta_1=n_2\sin\theta_2

sinθ2=n1sinθ1n2=1.04sin83°2.10.4915sin\theta_2=\frac{n_1\sin\theta_1}{n_2}=\frac{1.04\sin83\degree}{2.1}\approx0.4915

θ2=29.44°\theta_2 = 29.44\degree


Answer: θ2=29.44°\text{Answer: }\theta_2 = 29.44\degree


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS