1λ=R(112−1n2), ⟹ \frac 1{\lambda}=R(\frac 1{1^2}-\frac{1}{n^2}),\impliesλ1=R(121−n21),⟹
n=11−1λR=2n=\frac 1{\sqrt{1-\frac1{\lambda R}}}=2n=1−λR11=2 (ans. b).
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