light of wavelength 450 nm is incident on a diffraction grating on which 5000 lines can ruled out determine the angle corresponding to third order
5000 lines/cm=500000 lines/md=1500000=2×10−6d×sinθ=m×λ5000 \;lines/cm = 500000 \;lines/m \\ d = \frac{1}{500000}=2 \times 10^{-6} \\ d \times sin θ = m \times λ5000lines/cm=500000lines/md=5000001=2×10−6d×sinθ=m×λ
for third order m = 3
sinθ=3λdsinθ=3×450×10−92×10−6sinθ=0.675θ=71.67°sin θ = \frac{3λ }{d} \\ sin θ = \frac{3 \times 450 \times 10^{-9}}{2 \times 10^{-6}} \\ sin θ = 0.675 \\ θ = 71.67°sinθ=d3λsinθ=2×10−63×450×10−9sinθ=0.675θ=71.67°
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