Answer to Question #234771 in Optics for Sridhar

Question

A person wants to resolve two thin poles standing near each other from the distance of 2km.The minimum separation between poles should be nearly (theta=1 arc min )
1) 30 cm
2)40cm
3)60 cm
4)120 cm

Answer 1

$\theta= 1\text{arc min}$

$1\text{arc min}= \frac{1}{60\degree}=\frac{1}{60}*\frac{\pi}{180}\approx0.0003\text{ rad}$

$r = 2km = 2000m$

$\theta=\frac{l}{r}$

$l =\theta r=0.0003*2000= 0.6m = 60cm$

$\text{Answer: }3)60 cm$