Question #234771
A person wants to resolve two thin poles standing near each other from the distance of 2km.The minimum separation between poles should be nearly (theta=1 arc min )
1) 30 cm
2)40cm
3)60 cm
4)120 cm
1
Expert's answer
2021-09-09T10:50:12-0400

θ=1arc min\theta= 1\text{arc min}

1arc min=160°=160π1800.0003 rad1\text{arc min}= \frac{1}{60\degree}=\frac{1}{60}*\frac{\pi}{180}\approx0.0003\text{ rad}

r=2km=2000mr = 2km = 2000m

θ=lr\theta=\frac{l}{r}

l=θr=0.00032000=0.6m=60cml =\theta r=0.0003*2000= 0.6m = 60cm


Answer: 3)60cm\text{Answer: }3)60 cm


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