Answer to Question #232465 in Optics for Piyush

Question

In Newton's ring experiment,the diameter of 10th ring changes from 1.40cm to 1.27cm when a liquid is introduced between the lens and the plate.to calculate the refractive index of the liquid.

Answer 1

given that,

$D_{n} (air) = 1.4 cm, D_{n} (liquid) = 1.27 cm$

we can find the refractive index by using this formula also,

$\mu=\frac{D_{n}^2(air)}{D_{n}^2(liquid)}$

$=\frac{(1.4)^2}{(1.27)^2}$

$=1.215$