Answer to Question #22086 in Optics for khadijah

Question

What mass of silver nitrate, AgNO3, is needed to make 0.50 L of a 0.10 mol/L solution?

Answer 1

For answering this question you need to calculate amount of mol in final mixture.

0.10 mol per& 1 L
x in& 0.50 L

x=0.05 mol

Now you can calculate mass of silver nitrate, AgNO3:

n= m/Mw

m=n* Mw& ( Mw of AgNO3 = 169.87)

m=169.87 * 0.05= 8.4935