A transparent plastic has been developed. When light travels through it, it only travels at 3 × 107 m/s. What will be the refractive index of this new plastic?
n=cv,n=\frac cv,n=vc,
n=3⋅1083⋅107=10.n=\frac{3\cdot 10^8}{3\cdot 10^7}=10.n=3⋅1073⋅108=10.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments