Answer to Question #215902 in Optics for Fahim

Question #215902
A spring is hanging vertically from a fixed point and loaded with a mass of 500 g to its free end, which causes it to stretch by 20.0 cm from its initial length. What is the value of the spring constant?
(-/2.5 Points)
1
Expert's answer
2021-07-12T12:15:34-0400

Δx=20cm=0.2m\Delta x= 20 cm = 0.2m

m=500g=0.5kgm = 500g =0.5kg

g=9.8ms2g = 9.8\frac{m}{s^2}

F=mg=0.59.8=4.9N\vec F=mg=0.5*9.8=4.9N

F=kΔx\vec F=k\Delta x

k=FΔx=4.90.2=24.5Nmk=\frac{\vec F}{\Delta x}=\frac{4.9}{0.2}=24.5\frac{N}{m}

Answer: k=24.5Nm\text{Answer: }k=24.5\frac{N}{m}



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