A plano convex lens( μ=1.5) with radius of curvature 20 cm is silvered at the curved surface. The power of the system is..?
Answer:-
Given
μ=1.5 ,R1=∞ ,R2=−20cm(the object lies on the plane side)\mu =1.5 \ \ , R_1=\infin \ \ \ , \\R_2=-20cm (the \ object \ lies \ on \ the \ plane \ side)μ=1.5 ,R1=∞ ,R2=−20cm(the object lies on the plane side)
we know that
1f=(μ−1)(1R1−1R2)\frac{1}{f}=(\mu-1)(\frac{1}{R_1}-\frac{1}{R_2})f1=(μ−1)(R11−R21)
putting the values
1f=(1.5−1)(1∞−1−20)\frac{1}{f}=(1.5-1)(\frac{1}{\infin}-\frac{1}{-20})f1=(1.5−1)(∞1−−201)
1f=140f=40cm\frac{1}{f}=\frac{1}{40}\\ \boxed{f=40 cm}f1=401f=40cm
D=140cmD=\frac{1}{40cm}D=40cm1 [1 meter=100cm]
D=10040D=\frac{100}{40}D=40100
power=2.5 D\boxed{power=2.5 \ D}power=2.5 D
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