if the acceptance cone for the given fiber is 68.16 calculate the maximum entrance angle and numerical aperture if the cladding glass has a refractive index of a 1.52 calculate the refractive index of cone
"NA=n\\sin \\alpha=1.41,"
"\\alpha_{max}=\\alpha \\sqrt{ NA}=80.94\u00b0,"
"n'=NA=1.41."
Comments
Leave a comment