Question

A man stands 50cm from a concave mirror with radius of curvature 10cm. Find t position of the image and the magnification

Answer 1

Gives

Radius of curvature=10cm

u=50cm

$f=-\frac{1}{2}$ (Radius of curvature)

$f=-\frac{1}{2} \times10=5cm$

We know that

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$

$\frac{1}{v}=\frac{1}{f}-\frac{1}{u}$

$\frac{1}{v}=\frac{1}{-5}-\frac{1}{-50}$

$v=-\frac{50}{9}=-5.55cm$

Magnification

$M=\frac{v}{u}$

$M=\frac{-5.55}{-50}=0.12cm$