Question #211077

An electromagnetic wave in free space has an electric- eld vector E = f(t - z/c0).x, where ^x is a unit

vector in the x direction, and f(t) = e^-t^2=2

e^j2pv0t, where y is a constant. Describe the physical nature

of this wave and determine an expression for the magnetic- eld vector.


1
Expert's answer
2021-06-28T17:02:02-0400

Gives

E=f(tzc0)x^E=f(t-\frac{z}{c_0})\hat{x}

f(t)=et2,y=2ej2πv0t=2ejwtf(t)=e^{-t^2},y=2e^{j2\pi v_0t}=2e^{jwt}

We know that wave equation

y=Ae(jw0t+ϕ)y=Ae^{(jw_0t+\phi)}

Where A=amplitude

w0=w_0= Anguler frequency

ϕ\phi =phase

y=2ej2πv0t=2ejwt(1)y=2e^{j2\pi v_0t}=2e^{jwt}\rightarrow(1)

equation (1) is showing wave equation

equation (1)is

Phase

ϕ\phi =0°

Amplitude=2

Anguler frequency

w=2πv0w=2\pi v_0

Magnetic field vector

B=EcB=\frac{E}{c}

B=Ec=f(tzc0)x^cB=\frac{E}{c}=\frac{f(t-\frac{z}{c_0})\hat{x}}{c}

Where

f(t)=et2f(t)=e^{-t^2}


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