A student stands at a distance of 1.6 m in front of a camera with focal length of 5 cm, to obtain a sharp image on the film, how far must the lens be from the film?
Gives we
U=-1.6m
f=5cm
1v−1u=1f\frac{1}{v}-\frac{1}{u}=\frac{1}{f}v1−u1=f1
1v−1−1.6=1005\frac{1}{v}-\frac{1}{-1.6}=\frac{100}{5}v1−−1.61=5100
v=4.8cmv=4.8cmv=4.8cm
We know that
m=vu=d2d1m=\frac{v}{u}=\frac{d_2}{d_1}m=uv=d1d2
m=4.8−160=d25m=\frac{4.8}{-160}=\frac{d_2}{5}m=−1604.8=5d2
d2=0.15d_2=0.15d2=0.15 cm
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