A student stands at a distance of 1.6 m in front of a camera with focal length of 5 cm, to obtain a sharp image on the film, how far must the lens be from the film?
Gives we
U=-1.6m
f=5cm
"\\frac{1}{v}-\\frac{1}{u}=\\frac{1}{f}"
"\\frac{1}{v}-\\frac{1}{-1.6}=\\frac{100}{5}"
"v=4.8cm"
We know that
"m=\\frac{v}{u}=\\frac{d_2}{d_1}"
"m=\\frac{4.8}{-160}=\\frac{d_2}{5}"
"d_2=0.15" cm
Comments
Leave a comment