Answer to Question #205211 in Optics for Bukky

Question #205211

An object 7m high is placed 15cm from a convex spherical mirror of radius 45cm describe it's imagine


1
Expert's answer
2021-06-10T16:42:12-0400


Thus, the image is virtual erect and behind the mirror.

Write the expression for the focal length of the mirror

f=r2f=\frac{r}{2}

Here, f is the focal length and r is the radius of curvature.

Substitute 45 cm for r in the above expression.

f=452=22.5  cmf =\frac{45}{2}=22.5 \;cm

Write the expression for the mirror formula.

1v+1v=1f\frac{1}{v} + \frac{1}{v}= \frac{1}{f}

Substitute -15 cm for u and 22.5 cm for f in the above expression.

1v+115=122.5v=9  cm\frac{1}{v} + \frac{1}{-15}= \frac{1}{22.5} \\ v= 9 \;cm

Write the expression for the height of the image.

hh=vu\frac{h`}{h}= \frac{-v}{u}

Substitute 9 cm for v, -15 cm for u and 7 cm for h' in the above expression.

h7=915h=4.2  cm\frac{h`}{7}= \frac{9}{-15} \\ h`=4.2 \;cm

Thus, the image is 9 cm behind the mirror, it is virtual, erect and the size of image is 4.2 cm.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment