Question

What is the Power in dipoters of diverging lens of focal length 0.4m,0.1m, 80mm

Answer 1

Power of lens of focal length 0.4 m = $\dfrac{1}{F(in\space m)}=\dfrac{1}{-0.4}=-2.5\space D$

Power of lens of focal length 0.1 m = $\dfrac{1}{F(in\space m)}=\dfrac{1}{-0.1}=-10\space D$

Power of lens of focal length 80 mm(0.08 m) = $\dfrac{1}{F(in\space m)}=\dfrac{1}{-0.08}=-12.5\space D$