Question

Find the maximum value of resolving power of a grating 3 cm wide having 5000 lines per cm, if the wavelength of light used is 5890 A0.

Answer 1

Answer:-

we know that the number of lines is 5000 lines per cm

$d=\frac{1}{5000}cm\\ d=2\times10^{-6}m\\$

now we have

$\theta=\frac{\lambda}{d}\\$

now we have resolving power given as

$RP=\frac{d}{\lambda}\\ RP=\frac{2\times10^{-6}}{5890\times 10^{-10}}$

$RP=3.4$