Question #202081

Two plane polarised light waves are propagating along the positive z-direction 

such that their electric field vectors are mutually perpendicular. These waves are 

superposed. Obtain the condition under which the resultant wave will be circularly 

polarised.


1
Expert's answer
2021-06-03T09:18:21-0400

Ex=A1cos(ωt),E_x=A_1\cos(\omega t),

Ey=A2cos(ωt+δ),E_y=A_2\cos(\omega t+\delta),

A1=A2,A_1=A_2, δ=±π2,\delta=±\frac{\pi}{2},

tanφ=EyEx=A2cos(ωt±π2)A1cos(ωt)=sin(ωt)cos(ωt)=tan(ωt).\tan \varphi=\frac{E_y}{E_x}=\frac{A_2\cos(\omega t±\frac{\pi}{2})}{A_1\cos(\omega t)}=\mp\frac{\sin(\omega t)}{\cos(\omega t)}=\mp \tan(\omega t).


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