The angular separation of a converging lens 3 cm in diameter and a focal length of 20 cm is .......
assume λ ( 550 nm )
Diameter, D=3 cm=3×10−2 mD=3 \space cm=3\times10^{-2}\space mD=3 cm=3×10−2 m
λ=550 nm=550×10−9 m\lambda=550\space nm=550\times10^{-9}\space mλ=550 nm=550×10−9 m
Angular Separation =1.22λD=1.22×550×10−93×10−2=\dfrac{1.22\lambda}{D}=\dfrac{1.22\times550\times10^{-9}}{3\times10^{-2}}=D1.22λ=3×10−21.22×550×10−9
=2.24×10−5 rad=2.24\times10^{-5}\space rad=2.24×10−5 rad
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