Suppose a 200 mm-focal length telephoto lens is being used to photograph mountains 10.0 km away.
(a) Where is the image? ______ m
(b) What is the height of the image of a 1000 m high cliff on one of the mountains? ______ m
The lens formula is used to obtain the image distance
"\\frac{1}{f}=\\frac{1}{u}+\\frac{1}{v}"
"\\frac{1}{v}=\\frac{1}{f}-\\frac{1}{u}"
"\\frac{1}{v}=\\frac{ 1}{0.2}-\\frac{1}{10000}"
"v\\approx 0.2 \\ meters"
image distance= 0.2m
To get the image height , magnification should first be calculated
"m=\\frac{imagedistance}{object distance}"
"m=\\frac{ 0.2}{10000}= 2\\times10^{-5}"
"m=\\frac{ height of image}{heightof object}"
"heightofimage= (2\\times10^{-5})\\times1000=0.02 m"
height of image in cm is 2 cm
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