Answer to Question #200382 in Optics for Piolo

Question

What is Brewster’s angle for light traveling in water that is reflected from glass (n=1.589)?

answer to 3 decimal places

Answer 1

The special angle of incidence that produces a 90^o angle between the reflected and refracted ray is called the Brewster angle, $θ_p.$

and $\tan\theta _p=\dfrac{n_2}{n_1}$

here,

$n_1=1\ and\ \\n_2=1.589$

So, $\theta_p\degree=tan^{-1}(\dfrac{1.589}{1})=tan^{-1}(1.589)$

$\theta_p=57.81670025$

Answer:

Brewster's Angle $\boxed{\theta_p= 57.817\degree}$