Answer to Question #197044 in Optics for Vishal Kumar

Question

CALCULATE THE DISTANCE BETWEEN SUCCESSIVE POSITION OF THE MOVABLE MIRROR OF MICHELSONS INTERFEROMETER GIVING BEST FRINGES OF SODIUM SOURCE HAVING LINES 5896 A° AND 5890 A°.

Answer 1

$\lambda_1=5890, \lambda_2=5896$

As Difference in wavelength-

$\Delta \lambda=\lambda_1-\lambda_2=\dfrac{\lambda_1 \lambda_2}{2(x_2-x_1)}$

$(x_2-x_1)=\dfrac{\lambda_1 \lambda_2}{2\Delta \lambda}$

$=\dfrac{ 5.896\times 10^{-7} \times 5.890\times 10^{-7}}{2(5896-5890}$

$(x_2-x_1)=28.94 A$