The subject is at a distance of d = 1.8 meters from the lens. Determine the focal length of the lens if the image size is 5 times the size of the subject.
Object distance, u=−1.8 mu=-1.8\space mu=−1.8 m
Image distance =v=v=v
Magnification, m=5m=5m=5
m=vum=\dfrac{v}{u}m=uv
v=−5×1.8=−9 mv=-5\times 1.8=-9\space mv=−5×1.8=−9 m
Lens formula,
1v−1u=1f\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}v1−u1=f1
1f=−19+11.8\dfrac{1}{f}=-\dfrac{1}{9}+\dfrac{1}{1.8}f1=−91+1.81
f=2.25 mf=2.25\space mf=2.25 m
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