Question #191418

While building your first telescope, your nerd friend suggested a brilliant idea for you to try and replace the reflecting mirror of the telescope by a fisk of mercury rotating about a vertical axis with some angular velocity w that forms a spherical surface of radius R, in such a telescope, the the focal length of the telescope would be function of the rotating speed of the mercury disk, calculate how much angular velocity is needed for the telescope to have a focal length of 15 cm?



1
Expert's answer
2021-05-11T16:54:21-0400

Focal length of the telescope (f)=15cm

So, radius of the curved surface (R)=2f=30cm(R)=2f = 30cm

Angular velocity (V)=Rω(V)= R\omega

Or we can write it as (R)=Vω(R)=\frac{V}{\omega}

2f=Vω\Rightarrow 2f= \frac{V}{\omega}


30=Vω\Rightarrow 30=\frac{V}{\omega}


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