Question #191266

For a step index fibre with a core of refractive index of 1.54 and cladding refractive index 1.5 calculate the following when fibre is kept in water

b)Numerical aperture

c)Acceptance angle

d)Numerical Aperture in air


1
Expert's answer
2021-05-10T12:17:26-0400

Core refracting index, μ1=1.54\mu_1=1.54

Cladding refracting index, μ2=1.50\mu_2=1.50

Refractive index of air, μo=1\mu_o=1


(b) Numerical Aperture, (NA)=μ12μ22(NA)=\sqrt{\mu_1^2-\mu_2^2}

=(1.54)2(1.50)2=0.348=\sqrt{(1.54)^2-(1.50)^2}=0.348


(c) Acceptance angle, θa=sin1(NA)=sin1(0.348)=20.40°\theta_a=sin^{-1}(NA)=sin^{-1}(0.348)=20.40\degree


(d) Numerical aperture in air =μ12μo2=\sqrt{\mu_1^2-\mu_o^2}

=(1.54)212=1.17=\sqrt{(1.54)^2-1^2}=1.17


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