Answer to Question #188759 in Optics for Ahmad

Question #188759

Consider a step-index fiber for which n1 = 1.475, n2 = 1.460 and a = 25µm. What is the maximum value of θ for which the ray ill be guided by the fiber.

Expert's answer

"\\sin \\theta=\\sqrt{n_1^2-n_2^2},"

"\\sin\\theta=\\sqrt{1.475^2-1.46^2}=0.209,"

"\\theta=12.1\u00b0."

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