Question

The distance between mirror and an object placed in front of it 1.0m If rages of curvature of the mirror 4.0, the image formed will be

Answer 1

Answer

Focal length of mirror

f=0.25

u=1

Using

$\frac{1}{u}+\frac{1}{v}=\frac{1}{f}$

$v=\frac{uf}{u-f}=\frac{1\times0.25}{1-0.25}=0.33m\\=33cm$