Answer to Question #184287 in Optics for Abhijeet Pundir

Question #184287

The radius of the fifth zone of a zone plate is 2 mm. Considering the zone plate as a converging lens, calculate its focal length for light of wavelength 4800 Å


1
Expert's answer
2021-04-26T18:18:53-0400

Answer

Given data in question

r5=0.002mr_5=0.002m

n=5

λ=4800×1010m\lambda=4800\times10^{-10}m

Thus, the focal length of the zone plate,

f=rn2nλ=(0.002)25×4800×1010=166.67mf =\frac{ r_n^2}{n\lambda}\\= \frac{ (0.002)^2}{5\times 4800\times10^{-10} } \\=166.67m






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