Answer to Question #182699 in Optics for Khushi

Question

Derive an expression for the displacement of the nth bright fringe in Young’s

double-slit experiment when a thin transparent plate of refractive index  and

thickness t is introduced in the path of one of the constituent interfering beams of

light. Will there be any change in the fringe-width after the introduction of the

plate?

Answer 1

When a thin transparent plate of thickness ‘t’ is introduced in front of one of the slits in Young’s double slit experiment, the fringe pattern shifts toward the side where the plate is present.

The dotted lines denote the path of the light before introducing the transparent plate. The solid lines denote the path of the light after introducing a transparent plate.

Path difference before introducing the plate $\Delta x=S_1P-S_2P$

Path Difference after introducing the plate $\Delta x_{new}=S_1P_1-S_2P_1$

The path length $S_2P_1=(S_2P_1-t)_{air}+t_{plate}=(S_2P_1-t_{air})+(\mu t)_{plate}$

where '$\mu t$ ' is optical path.

$=S_2P_{1air}+(\mu -1)t$

Then we get

$(\Delta x)_{new}=S_1P_{1air}-(S_2P_{1air}+(\mu -1)t)=(S_1P_1-S_2P_1)_{air}-(\mu-1)t\\(\Delta x)_{new}=dsin\theta-(\mu-1)t(\Delta x)_{new}=\frac{\gamma d}{D}-(\mu-1)t\\$

Then,

$y=\frac{\Delta x D}{d}+\frac{D}{d}[(\mu-1)t]$

The term $\frac{\Delta x D}{d}$ defines the position of a bright or dark fringe, the term $\frac{D}{d}[(\mu-1)t]$ defines the shift occurred in the particular fringe due to the introduction of a transparent plate.